Consider below simple table:

Name Salary --------------- abc 100000 bcd 1000000 efg 40000 ghi 500000

How to find the employee whose salary is second highest. For example, in above table, “ghi” has the second highest salary as 500000.

Below is simple query to find the employee whose salary is highest.

SELECT name, MAX(salary) as salary FROM employee

We can nest the above query to find the second largest salary.

SELECT name, MAX(salary) AS salary FROM employee WHERE salary < (SELECT MAX(salary) FROM employee);

There are other ways also as suggested by RajnishKrJha.

SELECT name, MAX(salary) AS salary FROM employee WHERE salary IN (SELECT salary FROM employee MINUS SELECT MAX(salary) FROM employee);

SELECT name, MAX(salary) AS salary FROM employee WHERE salary (SELECT MAX(salary) FROM employee);

One way as suggested by **Arka Poddar**.

IN SQL Server using Common Table Expression or **CTE**, we can find the second highest salary:

WITH T AS ( SELECT * DENSE_RANK() OVER (ORDER BY Salary Desc) AS Rnk FROM Employees ) SELECT Name FROM T WHERE Rnk=2;

**How to find the third largest salary?**

Simple, we can do one more nesting.

SELECT name, MAX(salary) AS salary FROM employee WHERE salary < (SELECT MAX(salary) FROM employee WHERE salary < (SELECT MAX(salary) FROM employee) );

Note that instead of nesting for second, third largest salary, we can find nth salary using general query like in mysql:

select salary from employee order by salary desc limit n-1,1; Or Select name,salary from employee A where n-1 = (Select count(1) from employee B where B.salary>A.salary)

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