Regular Expression in Python with Examples | Set 1
The module re provides support for regular expressions in Python. Below are main methods in this module.
re.search() : This method either returns None (if the pattern doesn’t match), or a re.MatchObject that contains information about the matching part of the string. This method stops after the first match, so this is best suited for testing a regular expression more than extracting data.
# A Python program to demonstrate working of re.match(). import re # Lets use a regular expression to match a date string # in the form of Month name followed by day number regex = r"([a-zA-Z]+) (d+)" match = re.search(regex, "I was born on June 24") if match != None: # We reach here when the expression "([a-zA-Z]+) (d+)" # matches the date string. # This will print [14, 21), since it matches at index 14 # and ends at 21. print "Match at index %s, %s" % (match.start(), match.end()) # We us group() method to get all the matches and # captured groups. The groups contain the matched values. # In particular: # match.group(0) always returns the fully matched string # match.group(1) match.group(2), ... return the capture # groups in order from left to right in the input string # match.group() is equivalent to match.group(0) # So this will print "June 24" print "Full match: %s" % (match.group(0)) # So this will print "June" print "Month: %s" % (match.group(1)) # So this will print "24" print "Day: %s" % (match.group(2)) else: print "The regex pattern does not match." |
Output :
Match at index 14, 21 Full match: June 24 Month: June Day: 24
re.match() : This function attempts to match pattern to whole string. The re.match function returns a match object on success, None on failure.
re.match(pattern, string, flags=0)
pattern : Regular expression to be matched.
string : String where p attern is searched
flags : We can specify different flags
using bitwise OR (|).
# A Python program to demonstrate working # of re.match(). import re # a sample function that uses regular expressions # to find month and day of a date. def findMonthAndDate(string): regex = r"([a-zA-Z]+) (d+)" match = re.match(regex, string) if match == None: print "Not a valid date" return print "Given Data: %s" % (match.group()) print "Month: %s" % (match.group(1)) print "Day: %s" % (match.group(2)) # Driver Code findMonthAndDate("Jun 24") print("") findMonthAndDate("I was born on June 24") |
re.findall() : Return all non-overlapping matches of pattern in string, as a list of strings. The string is scanned left-to-right, and matches are returned in the order found (Source : Python Docs).
# A Python program to demonstrate working of # findall() import re # A sample text string where regular expression # is searched. string = """Hello my Number is 123456789 and my friend's number is 987654321""" # A sample regular expression to find digits. regex = 'd+' match = re.findall(regex, string) print(match) # This example is contributed by Ayush Saluja. |
Output :
['123456789', '987654321']
Regular expression is a vast topic. It’s a complete library. Regular expressions can do a lot of stuff. You can Match, Search, Replace, Extract a lot of data. For example, below small code is so powerful that it can extract email address from a text. So we can make our own Web Crawlers and scrappers in python with easy.Look at below regex.
# extract all email addresses and add them into the resulting set new_emails = set(re.findall(r"[a-z0-9.-+_][email protected][a-z0-9.-+_]+.[a-z]+", text, re.I))
We will soon be discussing more methods on regular expressions.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above
leave a comment
0 Comments