What will be the output of the following C program?
#include <stdio.h> int main() { int a = 3, b = -8, c = 2; printf("%d", a % b / c); return 0; } |
Output
1
% and / have same precedence and left to right associativity. So % is performed first which results in 3 and / is performed next resulting in 1. The emphasis is, sign of left operand is appended to result in case of modulus operator in C.
#include <stdio.h> int main() { // a positive and b negative. int a = 3, b = -8; printf("%d", a % b); return 0; } |
Output
3
#include <stdio.h> int main() { // a negative and b positive int a = -3, b = 8; printf("%d", a % b); return 0; } |
Output
-3
#include <stdio.h> int main() { // a and b both negative int a = -3, b = -8; printf("%d", a % b); return 0; } |
Output
-3
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