The ispunct() function checks whether a character is a punctuation character or not.
The term “punctuation” as defined by this function includes all printable characters that are neither alphanumeric nor a space. For example ‘@’, ‘$’, etc.
This function is defined in ctype.h header file.
syntax:
int ispunct(int ch); ch: character to be checked. Return Value : function return nonzero if character is a punctuation character; otherwise zero is returned.
// Program to check punctuation #include <stdio.h> #include <ctype.h> int main() { // The puncuations in str are '!' and ',' char str[] = "welcome! to GeeksForGeeks, "; int i = 0, count = 0; while (str[i]) { if (ispunct(str[i])) count++; i++; } printf("Sentence contains %d punctuation" " characters.
", count); return 0; } |
Output:
Sentence contains 2 punctuation characters.
// C program to print all Punctuations #include <stdio.h> #include <ctype.h> int main() { int i; printf("All punctuation characters in C" " programming are:
"); for (i = 0; i <= 255; ++i) if (ispunct(i) != 0) printf("%c ", i); return 0; } |
Output:
All punctuation characters in C programming are:
! " # $ % & ' ( ) * +, - . / : ; ? @ [ ] ^ _ ` { | } ~
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