Flexible Array Members in a structure in C

Flexible Array Member(FAM) is a feature introduced in the C99 standard of the C programming language.

  • For the structures in C programming language from C99 standard onwards, we can declare an array without a dimension and whose size is flexible in nature.
  • Such an array inside the structure should preferably be declared as the last member of structure and its size is variable(can be changed be at runtime).
  • The structure must contain at least one more named member in addition to the flexible array member.

What must be the size of the structure below?

struct student
   int stud_id;
   int name_len;
   int struct_size;
   char stud_name[];

The size of structure is = 4 + 4 + 4 + 0 = 12

In the above code snippet, the size i.e length of array “stud_name” isn’t fixed and is an FAM.

The memory allocation using flexible array members(as per C99 standards) for the above example can be done as:

 struct student *s = malloc( sizeof(*s) + sizeof(char [strlen(stud_name)])  );

Note: While using flexible array members in structures some convention regarding actual size of the member is defined.
In the above example the convention is that the member “stud_name” has character size.

For Example, Consider the following structure:

Input : id = 15, name = "Kartik" 
Output : Student_id : 15
         Stud_Name  : Kartik
         Name_Length: 6
         Allocated_Struct_size: 18

Memory allocation of above structure:

struct student *s = 
        malloc( sizeof(*s) + sizeof(char [strlen("Kartik")]));

Its structure representation is equal to:

struct student
   int stud_id;
   int name_len;
   int struct_size;
   char stud_name[6]; //character array of length 6


// C program for variable length members in
// structures in GCC
// A structure of type student
struct student
    int stud_id;
    int name_len;
    // This is used to store size of flexible
    // character array stud_name[]
    int struct_size;
    // Flexible Array Member(FAM)
    // variable length array must be last
    // member of structure
    char stud_name[];
// Memory allocation and initialisation of structure
struct student *createStudent(struct student *s,
                              int id, char a[])
    // Allocating memory according to user provided
    // array of characters
    s =
        malloc( sizeof(*s) + sizeof(char) * strlen(a));
    s->stud_id = id;
    s->name_len = strlen(a);
    strcpy(s->stud_name, a);
    // Assigning size according to size of stud_name
    // which is a copy of user provided array a[].
    s->struct_size =
        (sizeof(*s) + sizeof(char) * strlen(s->stud_name));
    return s;
// Print student details
void printStudent(struct student *s)
    printf("Student_id : %d "
           "Stud_Name : %s "
           "Name_Length: %d "
           "Allocated_Struct_size: %d ",
           s->stud_id, s->stud_name, s->name_len,
    // Value of Allocated_Struct_size is in bytes here
// Driver Code
int main()
    struct student *s1 = createStudent(s1, 523, "Cherry");
    struct student *s2 = createStudent(s2, 535, "Sanjayulsha");
    // Size in struct student
    printf("Size of Struct student: %lu ",
                    sizeof(struct student));
    // Size in struct pointer
    printf("Size of Struct pointer: %lu",
    return 0;


Student_id : 523
Stud_Name : SanjayKanna
Name_Length: 11
Allocated_Struct_size: 23

Student_id : 535
Stud_Name : Cherry
Name_Length: 6
Allocated_Struct_size: 18

Size of Struct student: 12
Size of Struct pointer: 8

Important Points:

  1. Adjacent memory locations are used to store structure members in memory.
  2. In previous standards of the C programming language, we were able to to declare a zero size array member in place of a flexible array member. The GCC compiler with C89 standard considers it as zero size array.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

This article is attributed to GeeksforGeeks.org

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