Write a C/C++ program that accepts a number from the user and prints “Even” if the entered number is even and prints “Odd” if the number is odd. You are not allowed to use any comparison (==, <,>,…etc) or conditional (if, else, switch, ternary operator,..etc) statement.
Method 1
Below is a tricky code can be used to print “Even” or “Odd” accordingly.
C++
#include<iostream> #include<conio.h> using namespace std; int main() { char arr[2][5] = {"Even", "Odd"}; int no; cout << "Enter a number: "; cin >> no; cout << arr[no%2]; getch(); return 0; } |
Python3
arr = ["Even", "Odd"] print ("Enter the number") no = input() print (arr[int(no) % 2]) |
PHP
Method 2
Below is another tricky code can be used to print “Even” or “Odd” accordingly. Thanks to student for suggesting this method.
#include<stdio.h> int main() { int no; printf("Enter a no: "); scanf("%d", &no); (no & 1 && printf("odd"))|| printf("even"); return 0; } |
Please write comments if you find the above code incorrect, or find better ways to solve the same problem
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