Program to check if a given year is leap year

A year is leap year if the following conditions are satisfied:

Year is multiple of 400.
Year is multiple of 4 and not multiple of 100.

Following is pseudo code

if year is divisible by 400 then is_leap_year
else if year is divisible by 100 then not_leap_year
else if year is divisible by 4 then is_leap_year
else not_leap_year

C++

// C++ program to check if a given  
// year is leap year or not  
#include <bits/stdc++.h> 
using namespace std;  
  
bool checkYear(int year)  
{  
    // If a year is multiple of 400,  
    // then it is a leap year  
    if (year % 400 == 0)  
        return true;  
  
    // Else If a year is muliplt of 100,  
    // then it is not a leap year  
    if (year % 100 == 0)  
        return false;  
  
    // Else If a year is muliplt of 4,  
    // then it is a leap year  
    if (year % 4 == 0)  
        return true;  
    return false;  
}  
  
// Driver code  
int main()  
{  
    int year = 2000;  
  
    checkYear(year) ? cout << "Leap Year":  
                      cout << "Not a Leap Year";  
    return 0;  
}  
  
// This is code is contributed  
// by rathbhupendra 

C

// C program to check if a given  
// year is leap year or not 
#include <stdio.h> 
#include <stdbool.h> 
  
bool checkYear(int year) 
{ 
    // If a year is multiple of 400,  
    // then it is a leap year 
    if (year % 400 == 0) 
        return true; 
  
    // Else If a year is muliplt of 100, 
    // then it is not a leap year 
    if (year % 100 == 0) 
        return false; 
  
    // Else If a year is muliplt of 4, 
    // then it is a leap year 
    if (year % 4 == 0) 
        return true; 
    return false; 
} 
  
// driver code 
int main() 
{ 
    int year = 2000; 
  
    checkYear(year)? printf("Leap Year"): 
                   printf("Not a Leap Year"); 
    return 0; 
} 

/div>

Java

// Java program to check 
// for a leap year 
      
class Test 
{ 
    static boolean checkYear(int year) 
    { 
        // If a year is multiple of 400,  
        // then it is a leap year 
        if (year % 400 == 0) 
            return true; 
      
        // Else If a year is muliplt of 100, 
        // then it is not a leap year 
        if (year % 100 == 0) 
            return false; 
      
        // Else If a year is muliplt of 4, 
        // then it is a leap year 
        if (year % 4 == 0) 
            return true; 
        return false; 
    } 
          
    // Driver method 
    public static void main(String[] args)  
    { 
        int year = 2000; 
        System.out.println( checkYear(2000)? "Leap Year" : 
                           "Not a Leap Year" ); 
    } 
} 

Python3

# Python program to check leap year or not 
def checkYear(year): 
    if (year % 4) == 0: 
        if (year % 100) == 0: 
            if (year % 400) == 0: 
                return True
            else: 
                return False
        else: 
             return True
    else: 
        return False
  
# Driver Code  
year = 2000
if(checkYear(year)): 
    print("Leap Year") 
else: 
    print("Not a Leap Year") 
      
# This code is contributed by Chinmoy Lenka  

C#

// C# program to check 
// for a leap year 
using System; 
  
class GFG 
{  
      
    static bool checkYear(int year) 
    { 
        // If a year is multiple of 400,  
        // then it is a leap year 
        if (year % 400 == 0) 
            return true; 
      
        // Else If a year is muliplt of 100, 
        // then it is not a leap year 
        if (year % 100 == 0) 
            return false; 
      
        // Else If a year is muliplt of 4, 
        // then it is a leap year 
        if (year % 4 == 0) 
            return true; 
        return false; 
    } 
          
    // Driver method 
    public static void Main() 
    { 
        int year = 2000; 
        Console.Write( checkYear(year)? "Leap Year" : 
                                 "Not a Leap Year" ); 
    } 
  
} 
  
// This code is contributed by Sam007 

PHP

<?php 
// PHP code to check if a given 
// year is leap year 
  
function checkYear($year)  
{  
    // If a year is multiple of 400,  
    // then it is a leap year  
    if ($year % 400 == 0)  
        print("Leap Year"); 
          
    // Else If a year is muliplt of 100,  
    // then it is not a leap year  
    else if ($year % 100 == 0)  
        print("Not a Leap Year"); 
              
    // Else If a year is multiple of 4,  
    // then it is a leap year  
    else if ($year % 4 == 0)  
        print("Leap Year"); 
          
    else
        print("Not a Leap Year");  
}  
  
// Driver code  
$year = 2000;  
  
checkYear($year); 
      
// This code is contributed by ash264 
?> 

Output:

Leap Year

How to write above code in one line?

C++

// One line C program to check if a
// given year is leap year or not
#include
using namespace std;

bool checkYear(int year)
{

// Return true if year is a multiple
// 0f 4 and not multiple of 100.
// OR year is multiple of 400.
return (((year % 4 == 0) && (year % 100 != 0)) ||
(year % 400 == 0));
}

// Driver code
int main()
{
int year = 2000;

checkYear(year)? cout << "Leap Year": cout << "Not a Leap Year"; return 0; } // This code is contributed by Akanksha Rai [tabby title="C"]

// One line C program to check if a  
// given year is leap year or not 
#include <stdio.h> 
#include <stdbool.h> 
  
bool checkYear(int year) 
{ 
// Return true if year is a multiple 
// 0f 4 and not multiple of 100. 
// OR year is multiple of 400. 
return (((year % 4 == 0) && (year % 100 != 0)) || 
        (year % 400 == 0)); 
} 
  
// driver code 
int main() 
{ 
    int year = 2000; 
  
    checkYear(year)? printf("Leap Year"): 
                printf("Not a Leap Year"); 
    return 0; 
} 

Java

// Java program to check 
// for a leap year 
      
class Test 
{ 
    static boolean checkYear(int year) 
    { 
    // Return true if year is a multiple 
    // of 4 and not multiple of 100. 
    // OR year is multiple of 400. 
    return (((year % 4 == 0) && (year % 100 != 0)) || 
            (year % 400 == 0)); 
    } 
          
    // Driver method 
    public static void main(String[] args)  
    { 
        int year = 2000; 
        System.out.println(checkYear(2000)? "Leap Year" : 
                           "Not a Leap Year" ); 
    } 
} 

Python3

# Python program to check leap year 
# or not in a single line 
  
def checkYear(year): 
  
    # Return true if year is a multiple 
    # of 4 and not multiple of 100. 
    # OR year is multiple of 400. 
    return (((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0)); 
  
# Driver Code  
year = 2000
if(checkYear(year)): 
    print("Leap Year") 
else: 
    print("Not a Leap Year") 
      
# This code is contributed by Chinmoy Lenka 

C#

// C# program to check 
// for a leap year 
using System; 
  
class GFG 
{  
    static bool checkYear(int year) 
    { 
        // Return true if year is a multiple 
        // of 4 and not multiple of 100. 
        // OR year is multiple of 400. 
        return (((year % 4 == 0) && (year % 100 != 0)) || 
                (year % 400 == 0)); 
    } 
          
    // Driver method 
    public static void Main() 
    { 
        int year = 2000; 
        Console.Write( checkYear(year)? "Leap Year" : 
                                 "Not a Leap Year" ); 
    } 
  
} 
// This code is contributed by Sam007 

PHP

<?php 
// PHP code to check if a given 
// year is leap year 
  
function checkYear($year)  
{  
      
    // Return true if year is a multiple  
    // 0f 4 and not multiple of 100.  
    // OR year is multiple of 400.  
    return ((($year % 4 == 0) &&  
             ($year % 100 != 0)) ||  
             ($year % 400 == 0)); 
}  
  
// Driver code  
$year = 2000;  
  
checkYear($year)? print("Leap Year"):  
                  print("Not a Leap Year"); 
  
// This code is contributed by ash264 
?> 

Output:

Leap Year

Program to check if a given year is leap year

C++

C

Java

Python3

C#

PHP

C++

Java

Python3

C#

PHP

tags:

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