# Program to check if a given year is leap year

A year is leap year if the following conditions are satisfied:

1. Year is multiple of 400.
2. Year is multiple of 4 and not multiple of 100.

Following is pseudo code

if year is divisible by 400 then is_leap_year
else if year is divisible by 100 then not_leap_year
else if year is divisible by 4 then is_leap_year
else not_leap_year

## C++

 // C++ program to check if a given  // year is leap year or not  #include using namespace std;     bool checkYear(int year)  {      // If a year is multiple of 400,      // then it is a leap year      if (year % 400 == 0)          return true;         // Else If a year is muliplt of 100,      // then it is not a leap year      if (year % 100 == 0)          return false;         // Else If a year is muliplt of 4,      // then it is a leap year      if (year % 4 == 0)          return true;      return false;  }     // Driver code  int main()  {      int year = 2000;         checkYear(year) ? cout << "Leap Year":                        cout << "Not a Leap Year";      return 0;  }     // This is code is contributed  // by rathbhupendra

## C

 // C program to check if a given  // year is leap year or not #include #include    bool checkYear(int year) {     // If a year is multiple of 400,      // then it is a leap year     if (year % 400 == 0)         return true;        // Else If a year is muliplt of 100,     // then it is not a leap year     if (year % 100 == 0)         return false;        // Else If a year is muliplt of 4,     // then it is a leap year     if (year % 4 == 0)         return true;     return false; }    // driver code int main() {     int year = 2000;        checkYear(year)? printf("Leap Year"):                    printf("Not a Leap Year");     return 0; }

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## Java

 // Java program to check // for a leap year        class Test {     static boolean checkYear(int year)     {         // If a year is multiple of 400,          // then it is a leap year         if (year % 400 == 0)             return true;                // Else If a year is muliplt of 100,         // then it is not a leap year         if (year % 100 == 0)             return false;                // Else If a year is muliplt of 4,         // then it is a leap year         if (year % 4 == 0)             return true;         return false;     }                // Driver method     public static void main(String[] args)      {         int year = 2000;         System.out.println( checkYear(2000)? "Leap Year" :                            "Not a Leap Year" );     } }

## Python3

 # Python program to check leap year or not def checkYear(year):     if (year % 4) == 0:         if (year % 100) == 0:             if (year % 400) == 0:                 return True             else:                 return False         else:              return True     else:         return False    # Driver Code  year = 2000 if(checkYear(year)):     print("Leap Year") else:     print("Not a Leap Year")        # This code is contributed by Chinmoy Lenka

## C#

 // C# program to check // for a leap year using System;    class GFG {             static bool checkYear(int year)     {         // If a year is multiple of 400,          // then it is a leap year         if (year % 400 == 0)             return true;                // Else If a year is muliplt of 100,         // then it is not a leap year         if (year % 100 == 0)             return false;                // Else If a year is muliplt of 4,         // then it is a leap year         if (year % 4 == 0)             return true;         return false;     }                // Driver method     public static void Main()     {         int year = 2000;         Console.Write( checkYear(year)? "Leap Year" :                                  "Not a Leap Year" );     }    }    // This code is contributed by Sam007

## PHP



Output:

Leap Year

How to write above code in one line?

## C++

// One line C program to check if a
// given year is leap year or not
#include
using namespace std;

bool checkYear(int year)
{

// Return true if year is a multiple
// 0f 4 and not multiple of 100.
// OR year is multiple of 400.
return (((year % 4 == 0) && (year % 100 != 0)) ||
(year % 400 == 0));
}

// Driver code
int main()
{
int year = 2000;

checkYear(year)? cout << "Leap Year": cout << "Not a Leap Year"; return 0; } // This code is contributed by Akanksha Rai [tabby title="C"]

 // One line C program to check if a  // given year is leap year or not #include #include    bool checkYear(int year) { // Return true if year is a multiple // 0f 4 and not multiple of 100. // OR year is multiple of 400. return (((year % 4 == 0) && (year % 100 != 0)) ||         (year % 400 == 0)); }    // driver code int main() {     int year = 2000;        checkYear(year)? printf("Leap Year"):                 printf("Not a Leap Year");     return 0; }

## Java

 // Java program to check // for a leap year        class Test {     static boolean checkYear(int year)     {     // Return true if year is a multiple     // of 4 and not multiple of 100.     // OR year is multiple of 400.     return (((year % 4 == 0) && (year % 100 != 0)) ||             (year % 400 == 0));     }                // Driver method     public static void main(String[] args)      {         int year = 2000;         System.out.println(checkYear(2000)? "Leap Year" :                            "Not a Leap Year" );     } }

## Python3

 # Python program to check leap year # or not in a single line    def checkYear(year):        # Return true if year is a multiple     # of 4 and not multiple of 100.     # OR year is multiple of 400.     return (((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0));    # Driver Code  year = 2000 if(checkYear(year)):     print("Leap Year") else:     print("Not a Leap Year")        # This code is contributed by Chinmoy Lenka

## C#

 // C# program to check // for a leap year using System;    class GFG {      static bool checkYear(int year)     {         // Return true if year is a multiple         // of 4 and not multiple of 100.         // OR year is multiple of 400.         return (((year % 4 == 0) && (year % 100 != 0)) ||                 (year % 400 == 0));     }                // Driver method     public static void Main()     {         int year = 2000;         Console.Write( checkYear(year)? "Leap Year" :                                  "Not a Leap Year" );     }    } // This code is contributed by Sam007



Output:

Leap Year

## tags:

School Programming date-time-program