# Next Greater Element

Given an array, print the Next Greater Element (NGE) for every element. The Next greater Element for an element x is the first greater element on the right side of x in array. Elements for which no greater element exist, consider next greater element as -1.

Examples:
a) For any array, rightmost element always has next greater element as -1.
b) For an array which is sorted in decreasing order, all elements have next greater element as -1.
c) For the input array [4, 5, 2, 25}, the next greater elements for each element are as follows.

```Element       NGE
4      -->   5
5      -->   25
2      -->   25
25     -->   -1
```

d) For the input array [13, 7, 6, 12}, the next greater elements for each element are as follows.

```  Element        NGE
13      -->    -1
7       -->     12
6       -->     12
12     -->     -1
```

Method 1 (Simple)
Use two loops: The outer loop picks all the elements one by one. The inner loop looks for the first greater element for the element picked by outer loop. If a greater element is found then that element is printed as next, otherwise -1 is printed.

Thanks to Sachin for providing following code.

## C++

br>
 `// Simple C++ program to print ` `// next greater elements in a ` `// given array ` `#include ` `using` `namespace` `std; ` ` `  `/* prints element and NGE pair  ` `for all elements of arr[] of size n */` `void` `printNGE(``int` `arr[], ``int` `n) ` `{ ` `    ``int` `next, i, j; ` `    ``for` `(i = 0; i < n; i++) ` `    ``{ ` `        ``next = -1; ` `        ``for` `(j = i + 1; j < n; j++) ` `        ``{ ` `            ``if` `(arr[i] < arr[j]) ` `            ``{ ` `                ``next = arr[j]; ` `                ``break``; ` `            ``} ` `        ``} ` `        ``cout << arr[i] << ``" -- "`  `             ``<< next << endl; ` `    ``} ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `arr[] = {11, 13, 21, 3}; ` `    ``int` `n = ``sizeof``(arr)/``sizeof``(arr[0]); ` `    ``printNGE(arr, n); ` `    ``return` `0; ` `} ` ` `  `// This code is contributed  ` `// by Akanksha Rai(Abby_akku) `

## C

 `      `  `// Simple C program to print next greater elements ` `// in a given array ` `#include ` ` `  `/* prints element and NGE pair for all elements of ` `arr[] of size n */` `void` `printNGE(``int` `arr[], ``int` `n) ` `{ ` `    ``int` `next, i, j; ` `    ``for` `(i=0; i

## Java

 `// Simple Java program to print next  ` `// greater elements in a given array ` ` `  `class` `Main ` `{  ` `    ``/* prints element and NGE pair for  ` `     ``all elements of arr[] of size n */` `    ``static` `void` `printNGE(``int` `arr[], ``int` `n) ` `    ``{ ` `        ``int` `next, i, j; ` `        ``for` `(i=``0``; i

## Python

 `  `  `# Function to print element and NGE pair for all elements of list ` `def` `printNGE(arr): ` ` `  `    ``for` `i ``in` `range``(``0``, ``len``(arr), ``1``): ` ` `  `        ``next` `=` `-``1` `        ``for` `j ``in` `range``(i``+``1``, ``len``(arr), ``1``): ` `            ``if` `arr[i] < arr[j]: ` `                ``next` `=` `arr[j] ` `                ``break` `             `  `        ``print``(``str``(arr[i]) ``+` `" -- "` `+` `str``(``next``)) ` ` `  `# Driver program to test above function ` `arr ``=` `[``11``,``13``,``21``,``3``] ` `printNGE(arr) ` ` `  `# This code is contributed by Sunny Karira `

## C#

 `// Simple C# program to print next  ` `// greater elements in a given array ` `using` `System; ` ` `  `class` `GFG ` `{ ` `     `  `    ``/* prints element and NGE pair for  ` `    ``all elements of arr[] of size n */` `    ``static` `void` `printNGE(``int` `[]arr, ``int` `n) ` `    ``{ ` `        ``int` `next, i, j; ` `        ``for` `(i = 0; i < n; i++) ` `        ``{ ` `            ``next = -1; ` `            ``for` `(j = i + 1; j < n; j++) ` `            ``{ ` `                ``if` `(arr[i] < arr[j]) ` `                ``{ ` `                    ``next = arr[j]; ` `                    ``break``; ` `                ``} ` `            ``} ` `            ``Console.WriteLine(arr[i] + ``" -- "` `+ next); ` `        ``} ` `    ``} ` `     `  `    ``// driver code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `[]arr= {11, 13, 21, 3}; ` `        ``int` `n = arr.Length; ` `         `  `        ``printNGE(arr, n); ` `    ``} ` `} ` ` `  `// This code is contributed by Sam007 `

## PHP

 ` `

Output:

```11 -- 13
13 -- 21
21 -- -1
3 -- -1```

Time Complexity: O(n^2). The worst case occurs when all elements are sorted in decreasing order.

Method 2 (Using Stack)
1) Push the first element to stack.
2) Pick rest of the elements one by one and follow the following steps in loop.
….a) Mark the current element as next.
….b) If stack is not empty, compare top element of stack with next.
….c) If next is greater than the top element,Pop element from stack. next is the next greater element for the popped element.
….d) Keep popping from the stack while the popped element is smaller than next. next becomes the next greater element for all such popped elements
….e) Finally, push the next in the stack.
3) After the loop in step 2 is over, pop all the elements from stack and print -1 as next element for them.

Below is the implementation of above approach:

## C++

 `      `  `// A Stack based C++ program to find next ` `// greater element for all array elements. ` `#include ` `using` `namespace` `std; ` ` `  `/* prints element and NGE pair for all ` `elements of arr[] of size n */` `void` `printNGE(``int` `arr[], ``int` `n) { ` `  ``stack < ``int` `> s; ` ` `  `  ``/* push the first element to stack */` `  ``s.push(arr[0]); ` ` `  `  ``// iterate for rest of the elements ` `  ``for` `(``int` `i = 1; i < n; i++) { ` ` `  `    ``if` `(s.empty()) { ` `      ``s.push(arr[i]); ` `      ``continue``; ` `    ``} ` ` `  `    ``/* if stack is not empty, then ` `       ``pop an element from stack. ` `       ``If the popped element is smaller ` `       ``than next, then ` `    ``a) print the pair ` `    ``b) keep popping while elements are ` `    ``smaller and stack is not empty */` `    ``while` `(s.empty() == ``false` `&& s.top() < arr[i]) ` `    ``{          ` `        ``cout << s.top() << ``" --> "` `<< arr[i] << endl; ` `        ``s.pop(); ` `    ``} ` ` `  `    ``/* push next to stack so that we can find ` `    ``next greater for it */` `    ``s.push(arr[i]); ` `  ``} ` ` `  `  ``/* After iterating over the loop, the remaining ` `  ``elements in stack do not have the next greater ` `  ``element, so print -1 for them */` `  ``while` `(s.empty() == ``false``) { ` `    ``cout << s.top() << ``" --> "` `<< -1 << endl; ` `    ``s.pop(); ` `  ``} ` `} ` ` `  `/* Driver program to test above functions */` `int` `main() { ` `  ``int` `arr[] = {11, 13, 21, 3}; ` `  ``int` `n = ``sizeof``(arr) / ``sizeof``(arr[0]); ` `  ``printNGE(arr, n); ` `  ``return` `0; ` `}`

## C

 `// A Stack based C program to find next greater element ` `// for all array elements. ` `#include ` `#include ` `#include ` `#define STACKSIZE 100 ` ` `  `// stack structure ` `struct` `stack ` `{ ` `    ``int` `top; ` `    ``int` `items[STACKSIZE]; ` `}; ` ` `  `// Stack Functions to be used by printNGE() ` `void` `push(``struct` `stack *ps, ``int` `x) ` `{ ` `    ``if` `(ps->top == STACKSIZE-1) ` `    ``{ ` `        ``printf``(``"Error: stack overflown"``); ` `        ``getchar``(); ` `        ``exit``(0); ` `    ``} ` `    ``else` `    ``{ ` `        ``ps->top += 1; ` `        ``int` `top = ps->top; ` `        ``ps->items [top] = x; ` `    ``} ` `} ` ` `  `bool` `isEmpty(``struct` `stack *ps) ` `{ ` `    ``return` `(ps->top == -1)? ``true` `: ``false``; ` `} ` ` `  `int` `pop(``struct` `stack *ps) ` `{ ` `    ``int` `temp; ` `    ``if` `(ps->top == -1) ` `    ``{ ` `        ``printf``(``"Error: stack underflow n"``); ` `        ``getchar``(); ` `        ``exit``(0); ` `    ``} ` `    ``else` `    ``{ ` `        ``int` `top = ps->top; ` `        ``temp = ps->items [top]; ` `        ``ps->top -= 1; ` `        ``return` `temp; ` `    ``} ` `} ` ` `  `/* prints element and NGE pair for all elements of ` `arr[] of size n */` `void` `printNGE(``int` `arr[], ``int` `n) ` `{ ` `    ``int` `i = 0; ` `    ``struct` `stack s; ` `    ``s.top = -1; ` `    ``int` `element, next; ` ` `  `    ``/* push the first element to stack */` `    ``push(&s, arr[0]); ` ` `  `    ``// iterate for rest of the elements ` `    ``for` `(i=1; i %d"``, element, next); ` `                ``if``(isEmpty(&s) == ``true``) ` `                   ``break``; ` `                ``element = pop(&s); ` `            ``} ` ` `  `            ``/* If element is greater than next, then push ` `               ``the element back */` `            ``if` `(element > next) ` `                ``push(&s, element); ` `        ``} ` ` `  `        ``/* push next to stack so that we can find ` `           ``next greater for it */` `        ``push(&s, next); ` `    ``} ` ` `  `    ``/* After iterating over the loop, the remaining ` `       ``elements in stack do not have the next greater ` `       ``element, so print -1 for them */` `    ``while` `(isEmpty(&s) == ``false``) ` `    ``{ ` `        ``element = pop(&s); ` `        ``next = -1; ` `        ``printf``(``"n %d --> %d"``, element, next); ` `    ``} ` `} ` ` `  `/* Driver program to test above functions */` `int` `main() ` `{ ` `    ``int` `arr[]= {11, 13, 21, 3}; ` `    ``int` `n = ``sizeof``(arr)/``sizeof``(arr[0]); ` `    ``printNGE(arr, n); ` `    ``getchar``(); ` `    ``return` `0; ` `} `

## Java

 `//Java program to print next ` `//greater element using stack ` ` `  `public` `class` `NGE  ` `{ ` `    ``static` `class` `stack  ` `    ``{ ` `        ``int` `top; ` `        ``int` `items[] = ``new` `int``[``100``]; ` ` `  `        ``// Stack functions to be used by printNGE ` `        ``void` `push(``int` `x)  ` `        ``{ ` `            ``if` `(top == ``99``)  ` `            ``{ ` `                ``System.out.println(``"Stack full"``); ` `            ``}  ` `            ``else`  `            ``{ ` `                ``items[++top] = x; ` `            ``} ` `        ``} ` ` `  `        ``int` `pop()  ` `        ``{ ` `            ``if` `(top == -``1``)  ` `            ``{ ` `                ``System.out.println(``"Underflow error"``); ` `                ``return` `-``1``; ` `            ``}  ` `            ``else`  `            ``{ ` `                ``int` `element = items[top]; ` `                ``top--; ` `                ``return` `element; ` `            ``} ` `        ``} ` ` `  `        ``boolean` `isEmpty()  ` `        ``{ ` `            ``return` `(top == -``1``) ? ``true` `: ``false``; ` `        ``} ` `    ``} ` ` `  `    ``/* prints element and NGE pair for  ` `       ``all elements of arr[] of size n */` `    ``static` `void` `printNGE(``int` `arr[], ``int` `n)  ` `    ``{ ` `        ``int` `i = ``0``; ` `        ``stack s = ``new` `stack(); ` `        ``s.top = -``1``; ` `        ``int` `element, next; ` ` `  `        ``/* push the first element to stack */` `        ``s.push(arr[``0``]); ` ` `  `        ``// iterate for rest of the elements ` `        ``for` `(i = ``1``; i < n; i++)  ` `        ``{ ` `            ``next = arr[i]; ` ` `  `            ``if` `(s.isEmpty() == ``false``)  ` `            ``{ ` `                 `  `                ``// if stack is not empty, then  ` `                ``// pop an element from stack ` `                ``element = s.pop(); ` ` `  `                ``/* If the popped element is smaller than  ` `                   ``next, then a) print the pair b) keep  ` `                   ``popping while elements are smaller and  ` `                   ``stack is not empty */` `                ``while` `(element < next)  ` `                ``{ ` `                    ``System.out.println(element + ``" --> "` `+ next); ` `                    ``if` `(s.isEmpty() == ``true``) ` `                        ``break``; ` `                    ``element = s.pop(); ` `                ``} ` ` `  `                ``/* If element is greater than next, then  ` `                   ``push the element back */` `                ``if` `(element > next) ` `                    ``s.push(element); ` `            ``} ` ` `  `            ``/* push next to stack so that we can find next ` `               ``greater for it */` `            ``s.push(next); ` `        ``} ` ` `  `        ``/* After iterating over the loop, the remaining  ` `           ``elements in stack do not have the next greater  ` `           ``element, so print -1 for them */` `        ``while` `(s.isEmpty() == ``false``)  ` `        ``{ ` `            ``element = s.pop(); ` `            ``next = -``1``; ` `            ``System.out.println(element + ``" -- "` `+ next); ` `        ``} ` `    ``} ` ` `  `    ``public` `static` `void` `main(String[] args)  ` `    ``{ ` `        ``int` `arr[] = { ``11``, ``13``, ``21``, ``3` `}; ` `        ``int` `n = arr.length; ` `        ``printNGE(arr, n); ` `    ``} ` `} ` ` `  `// Thanks to Rishabh Mahrsee for contributing this code  `

## Python

 `# Python program to print next greater element using stack ` ` `  `# Stack Functions to be used by printNGE() ` `def` `createStack(): ` `    ``stack ``=` `[] ` `    ``return` `stack ` ` `  `def` `isEmpty(stack): ` `    ``return` `len``(stack) ``=``=` `0` ` `  `def` `push(stack, x): ` `    ``stack.append(x) ` ` `  `def` `pop(stack): ` `    ``if` `isEmpty(stack): ` `        ``print``(``"Error : stack underflow"``) ` `    ``else``: ` `        ``return` `stack.pop() ` ` `  `'''prints element and NGE pair for all elements of ` `   ``arr[] '''` `def` `printNGE(arr): ` `    ``s ``=` `createStack() ` `    ``element ``=` `0` `    ``next` `=` `0` ` `  `    ``# push the first element to stack ` `    ``push(s, arr[``0``]) ` ` `  `    ``# iterate for rest of the elements ` `    ``for` `i ``in` `range``(``1``, ``len``(arr), ``1``): ` `        ``next` `=` `arr[i] ` ` `  `        ``if` `isEmpty(s) ``=``=` `False``: ` ` `  `            ``# if stack is not empty, then pop an element from stack ` `            ``element ``=` `pop(s) ` ` `  `            ``'''If the popped element is smaller than next, then ` `                ``a) print the pair ` `                ``b) keep popping while elements are smaller and ` `                   ``stack is not empty '''` `            ``while` `element < ``next` `: ` `                ``print``(``str``(element)``+` `" -- "` `+` `str``(``next``)) ` `                ``if` `isEmpty(s) ``=``=` `True` `: ` `                    ``break` `                ``element ``=` `pop(s) ` ` `  `            ``'''If element is greater than next, then push ` `               ``the element back '''` `            ``if`  `element > ``next``: ` `                ``push(s, element) ` ` `  `        ``'''push next to stack so that we can find ` `           ``next greater for it '''` `        ``push(s, ``next``) ` ` `  `    ``'''After iterating over the loop, the remaining ` `       ``elements in stack do not have the next greater ` `       ``element, so print -1 for them '''` ` `  `    ``while` `isEmpty(s) ``=``=` `False``: ` `            ``element ``=` `pop(s) ` `            ``next` `=` `-``1` `            ``print``(``str``(element) ``+` `" -- "` `+` `str``(``next``)) ` ` `  `# Driver program to test above functions ` `arr ``=` `[``11``, ``13``, ``21``, ``3``] ` `printNGE(arr) ` ` `  `# This code is contributed by Sunny Karira `

## C#

 `using` `System; ` ` `  `// c# program to print next  ` `//greater element using stack  ` ` `  `public` `class` `NGE ` `{ ` `    ``public` `class` `stack ` `    ``{ ` `        ``public` `int` `top; ` `        ``public` `int``[] items = ``new` `int``[100]; ` ` `  `        ``// Stack functions to be used by printNGE  ` `        ``public` `virtual` `void` `push(``int` `x) ` `        ``{ ` `            ``if` `(top == 99) ` `            ``{ ` `                ``Console.WriteLine(``"Stack full"``); ` `            ``} ` `            ``else` `            ``{ ` `                ``items[++top] = x; ` `            ``} ` `        ``} ` ` `  `        ``public` `virtual` `int` `pop() ` `        ``{ ` `            ``if` `(top == -1) ` `            ``{ ` `                ``Console.WriteLine(``"Underflow error"``); ` `                ``return` `-1; ` `            ``} ` `            ``else` `            ``{ ` `                ``int` `element = items[top]; ` `                ``top--; ` `                ``return` `element; ` `            ``} ` `        ``} ` ` `  `        ``public` `virtual` `bool` `Empty ` `        ``{ ` `            ``get` `            ``{ ` `                ``return` `(top == -1) ? ``true` `: ``false``; ` `            ``} ` `        ``} ` `    ``} ` ` `  `    ``/* prints element and NGE pair for   ` `       ``all elements of arr[] of size n */` `    ``public` `static` `void` `printNGE(``int``[] arr, ``int` `n) ` `    ``{ ` `        ``int` `i = 0; ` `        ``stack s = ``new` `stack(); ` `        ``s.top = -1; ` `        ``int` `element, next; ` ` `  `        ``/* push the first element to stack */` `        ``s.push(arr[0]); ` ` `  `        ``// iterate for rest of the elements  ` `        ``for` `(i = 1; i < n; i++) ` `        ``{ ` `            ``next = arr[i]; ` ` `  `            ``if` `(s.Empty == ``false``) ` `            ``{ ` ` `  `                ``// if stack is not empty, then   ` `                ``// pop an element from stack  ` `                ``element = s.pop(); ` ` `  `                ``/* If the popped element is smaller than   ` `                   ``next, then a) print the pair b) keep   ` `                   ``popping while elements are smaller and   ` `                   ``stack is not empty */` `                ``while` `(element < next) ` `                ``{ ` `                    ``Console.WriteLine(element + ``" --> "` `+ next); ` `                    ``if` `(s.Empty == ``true``) ` `                    ``{ ` `                        ``break``; ` `                    ``} ` `                    ``element = s.pop(); ` `                ``} ` ` `  `                ``/* If element is greater than next, then   ` `                   ``push the element back */` `                ``if` `(element > next) ` `                ``{ ` `                    ``s.push(element); ` `                ``} ` `            ``} ` ` `  `            ``/* push next to stack so that we can find next  ` `               ``greater for it */` `            ``s.push(next); ` `        ``} ` ` `  `        ``/* After iterating over the loop, the remaining   ` `           ``elements in stack do not have the next greater   ` `           ``element, so print -1 for them */` `        ``while` `(s.Empty == ``false``) ` `        ``{ ` `            ``element = s.pop(); ` `            ``next = -1; ` `            ``Console.WriteLine(element + ``" -- "` `+ next); ` `        ``} ` `    ``} ` ` `  `    ``public` `static` `void` `Main(``string``[] args) ` `    ``{ ` `        ``int``[] arr = ``new` `int``[] {11, 13, 21, 3}; ` `        ``int` `n = arr.Length; ` `        ``printNGE(arr, n); ` `    ``} ` `} ` ` `  `// This code is contributed by Shrikant13 `

Output:

``` 11 -- 13
13 -- 21
3 -- -1
21 -- -1
```

Time Complexity: O(n^2). The worst case occurs when all elements are sorted in decreasing order. If elements are sorted in decreasing order, then every element is processed at most 4 times.
a) Initially pushed to the stack.
b) Popped from the stack when next element is being processed.
c) Pushed back to the stack because next element is smaller.
d) Popped from the stack in step 3 of algo.

How to get elements in same order as input?

The above approach may not produce output elements in same order as input. To achieve same order, we can traverse the same in reverse order

Below is the implementation of above approach:

## C++

 `// A Stack based C++ program to find next  ` `// greater element for all array elements  ` `// in same order as input.  ` `#include ` `  `  `using` `namespace` `std;  ` ` `  `/* prints element and NGE pair for all  ` `elements of arr[] of size n */` `void` `printNGE(``int` `arr[], ``int` `n)  ` `{  ` `    ``stack<``int``> s;  ` `    ``unordered_map<``int``, ``int``> mp;  ` ` `  `    ``/* push the first element to stack */` `    ``s.push(arr[0]);  ` `     `  ` `  `    ``// iterate for rest of the elements  ` `    ``for` `(``int` `i = 1; i < n; i++) {  ` ` `  `        ``if` `(s.empty()) {  ` `            ``s.push(arr[i]);  ` `            ``continue``;  ` `        ``}  ` ` `  `        ``/* if stack is not empty, then  ` `    ``pop an element from stack.  ` `    ``If the popped element is smaller  ` `    ``than next, then  ` `    ``a) print the pair  ` `    ``b) keep popping while elements are  ` `    ``smaller and stack is not empty */` `        ``while` `(s.empty() == ``false` `&& s.top() < arr[i]) {  ` `            ``mp[s.top()] = arr[i];  ` `            ``s.pop();  ` `        ``}  ` ` `  `        ``/* push next to stack so that we can find  ` `    ``next smaller for it */` `        ``s.push(arr[i]);  ` `    ``}  ` ` `  `    ``/* After iterating over the loop, the remaining  ` `elements in stack do not have the next smaller  ` `element, so print -1 for them */` `    ``while` `(s.empty() == ``false``) {  ` `        ``mp[s.top()] = -1;  ` `        ``s.pop();  ` `    ``}  ` ` `  `    ``for` `(``int` `i=0; i "` `<< mp[arr[i]] << endl;  ` `}  ` ` `  `/* Driver program to test above functions */` `int` `main()  ` `{  ` `    ``int` `arr[] = { 11, 13, 21, 3 };  ` `    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr[0]);  ` `    ``printNGE(arr, n);  ` `    ``return` `0;  ` `} `

## Java

 `// A Stack based Java program to find next  ` `// greater element for all array elements  ` `// in same order as input.  ` `import` `java.util.Stack; ` ` `  `class` `NextGreaterElement  ` `{ ` ` `  `    ``static` `int` `arr[] = {``11``, ``13``, ``21``, ``3``}; ` ` `  `    ``/* prints element and NGE pair for all  ` `    ``elements of arr[] of size n */` `    ``public` `static` `void` `printNGE()  ` `    ``{ ` `        ``Stack s = ``new` `Stack<>(); ` `        ``int` `nge[] = ``new` `int``[arr.length]; ` ` `  `        ``// iterate for rest of the elements  ` `        ``for` `(``int` `i = arr.length - ``1``; i >= ``0``; i--) { ` `             `  `            ``/* if stack is not empty, then  ` `            ``pop an element from stack.  ` `            ``If the popped element is smaller  ` `            ``than next, then  ` `            ``a) print the pair  ` `            ``b) keep popping while elements are  ` `            ``smaller and stack is not empty */` `            ``if` `(!s.empty()) { ` `                ``while` `(!s.empty() && s.peek() <= arr[i]) { ` `                    ``s.pop(); ` `                ``} ` `            ``} ` `            ``nge[i] = s.empty() ? -``1` `: s.peek(); ` `            ``s.push(arr[i]); ` ` `  `        ``} ` `        ``for``(``int` `i = ``0``; i < arr.length; i++)  ` `        ``System.out.println(arr[i] + ``" --> "` `+ nge[i]); ` `    ``} ` ` `  `/* Driver program to test above functions */` `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` `        ``//NextGreaterElement nge = new NextGreaterElement(); ` `        ``printNGE(); ` `    ``} ` `} ` `// This code is contributed by Ashish Goyal `

## C#

 `// A Stack based C# program to find next  ` `// greater element for all array elements  ` `// in same order as input.  ` `using` `System; ` `using` `System.Collections.Generic; ` ` `  `class` `GFG ` `{ ` `private` `int``[] arr = ``new` `int``[] {11, 13, 21, 3}; ` ` `  `/* prints element and NGE pair for all  ` `elements of arr[] of size n */` `private` `void` `printNGE() ` `{ ` `    ``Stack<``int``> s = ``new` `Stack<``int``>(); ` `    ``int``[] nge = ``new` `int``[arr.Length]; ` ` `  `    ``// iterate for rest of the elements  ` `    ``for` `(``int` `i = arr.Length - 1; i >= 0; i--) ` `    ``{ ` ` `  `        ``/* if stack is not empty, then  ` `        ``pop an element from stack.  ` `        ``If the popped element is smaller  ` `        ``than next, then  ` `        ``a) print the pair  ` `        ``b) keep popping while elements are  ` `        ``smaller and stack is not empty */` `        ``if` `(s.Count > 0) ` `        ``{ ` `            ``while` `(s.Count > 0 && s.Peek() <= arr[i]) ` `            ``{ ` `                ``s.Pop(); ` `            ``} ` `        ``} ` `        ``nge[i] = s.Count == 0 ? -1 : s.Peek(); ` `        ``s.Push(arr[i]); ` ` `  `    ``} ` `    ``for` `(``int` `i = 0; i < arr.Length; i++) ` `    ``{ ` `        ``Console.WriteLine(arr[i] + ``" --> "` `+ nge[i]); ` `    ``} ` `} ` ` `  `// Driver Code ` `public` `static` `void` `Main(``string``[] args) ` `{ ` `    ``GFG nge = ``new` `GFG(); ` `    ``nge.printNGE(); ` `} ` `} ` ` `  `// This code is contributed  ` `// by Shrikant13 `

Please see for optimized solution for printing in same order.

Please write comments if you find the above codes/algorithms incorrect, or find other ways to solve the same problem.

code