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Program to find size of Doubly Linked List

Given a doubly linked list, the task is to find the size of that doubly linked list. For example, size of below linked list is 4.

dll

A doubly linked list is a linked data structure that consists of a set of sequentially linked records called nodes. Each node contains two fields, called links, that are references to the previous and to the next node in the sequence of nodes.
Traversal of a doubly linked list can be in either direction. In fact, the direction of traversal can change many times, if desired.

For example the function should return 3 for the above doubly linked list.

Algorithm :

1) Initialize size to 0.
2) Initialize a node pointer, temp = head.
3) Do following while temp is not NULL
……a) temp = temp -> next
……b) size++;
4) Return size.

C++

// A complete working C++ program to
// find size of doubly linked list.
#include <bits/stdc++.h>
using namespace std;
  
// A linked list node
struct Node
{
    int data;
    struct Node *next;
    struct Node *prev;
};
  
/* Function to add a node to front of doubly
   linked list */
void push(struct Node** head_ref, int new_data)
{
    struct Node* new_node = new Node;
    new_node->data  = new_data;
    new_node->next = (*head_ref);
    new_node->prev = NULL;
    if ((*head_ref) !=  NULL)
      (*head_ref)->prev = new_node ;
    (*head_ref)    = new_node;
}
  
// This function returns size of linked list
int findSize(struct Node *node)
{
   int res = 0;
   while (node != NULL)
   {
       res++;
       node = node->next;
   }
   return res;
}
  
/* Drier program to test above functions*/
int main()
{
    struct Node* head = NULL;
    push(&head, 4);
    push(&head, 3);
    push(&head, 2);
    push(&head, 1);
    cout << findSize(head);
    return 0;
}

Java

// A complete working Java program to 
// find size of doubly linked list. 
import java.io.*;
import java.util.*;
  
// Represents a doubly linked list node
class Node 
{
    int data;
    Node next, prev;
    Node(int val)
    {
        data = val;
        next = null;
        prev = null;
    }
}
  
class GFG 
{
  
    /* Function to add a node to front of doubly 
    linked list */
    static Node push(Node head, int data)
    {
        Node new_node = new Node(data);
        new_node.next = head;
        new_node.prev = null;
        if (head != null)
            head.prev = new_node;
        head = new_node;
              
        return head;
    }
  
    // This function returns size of doubly linked list
    static int findSize(Node node)
    {
        int res = 0;
        while (node != null
        {
                res++;
                node = node.next;
        }
  
        return res;
    }
  
    // Driver Code
    public static void main(String args[])
    {
        Node head = null
        head = push(head, 4);
        head = push(head, 3);
        head = push(head, 2);
        head = push(head, 1);
        System.out.println(findSize(head));
    }
}
  
// This code is contributed by rachana soma

C#

// A complete working C# program to 
// find size of doubly linked list. 
 using System; 
  
// Represents a doubly linked list node 
public class Node 
    public int data; 
    public Node next, prev; 
    public Node(int val) 
    
        data = val; 
        next = null
        prev = null
    
  
class GFG 
  
    /* Function to add a node to front of doubly 
    linked list */
    static Node push(Node head, int data) 
    
        Node new_node = new Node(data); 
        new_node.next = head; 
        new_node.prev = null
        if (head != null
            head.prev = new_node; 
        head = new_node; 
              
        return head; 
    
  
    // This function returns size of doubly linked list 
    static int findSize(Node node) 
    
        int res = 0; 
        while (node != null
        
                res++; 
                node = node.next; 
        
  
        return res; 
    
  
    // Driver Code 
    public static void Main(String []args) 
    
        Node head = null
        head = push(head, 4); 
        head = push(head, 3); 
        head = push(head, 2); 
        head = push(head, 1); 
        Console.WriteLine(findSize(head)); 
    
  
// This code is contributed by Arnab Kundu

Output:

4


This article is attributed to GeeksforGeeks.org

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