# Get level of a node in binary tree | iterative approach

Given a Binary Tree and a key, write a function that returns level of the key.

For example, consider the following tree. If the input key is 3, then your function should return 1. If the input key is 4, then your function should return 3. And for key which is not present in key, then your function should return 0. Recursive approach to this problem is discussed here
https://tutorialspoint.dev/slugresolver/get-level-of-a-node-in-a-binary-tree/

The iterative approach is discussed below :
The iterative approach is modified version of Level Order Tree Traversal
Algorithm

```create a empty queue q
push root and then NULL to q
loop till q is not empty
get the front node into temp node
if it is NULL, it means all nodes of
one level are traversed, so increment
level
else
check if temp data is equal to data
to be searched
if yes then return level
if temp->left is not NULL,
enqueue temp->left
if temp->right is not NULL,
enqueue temp->right
```

## C++

 `// CPP program to print level of given node ` `// in binary tree iterative approach ` `/* Example binary tree ` `root is at level 1 ` ` `  `                ``20 ` `              ``/   ` `            ``10    30 ` `           ``/     / ` `          ``5  15  25  40 ` `             ``/ ` `            ``12  */` `#include ` `#include ` `using` `namespace` `std; ` ` `  `// node of binary tree ` `struct` `node { ` `    ``int` `data; ` `    ``node* left; ` `    ``node* right; ` `}; ` ` `  `// utility function to create ` `// a new node ` `node* getnode(``int` `data) ` `{ ` `    ``node* newnode = ``new` `node(); ` `    ``newnode->data = data; ` `    ``newnode->left = NULL; ` `    ``newnode->right = NULL; ` `} ` ` `  `// utility function to return level of given node ` `int` `getlevel(node* root, ``int` `data) ` `{ ` `    ``queue q; ` `    ``int` `level = 1; ` `    ``q.push(root); ` ` `  `    ``// extra NULL is pushed to keep track ` `    ``// of all the nodes to be pushed before ` `    ``// level is incremented by 1 ` `    ``q.push(NULL); ` `    ``while` `(!q.empty()) { ` `        ``node* temp = q.front(); ` `        ``q.pop(); ` `        ``if` `(temp == NULL) { ` `            ``if` `(q.front() != NULL) { ` `                ``q.push(NULL); ` `            ``} ` `            ``level += 1; ` `        ``} ``else` `{ ` `            ``if` `(temp->data == data) { ` `                ``return` `level; ` `            ``} ` `            ``if` `(temp->left) { ` `                ``q.push(temp->left); ` `            ``} ` `            ``if` `(temp->right) { ` `                ``q.push(temp->right); ` `            ``} ` `        ``} ` `    ``} ` `    ``return` `0; ` `} ` ` `  `int` `main() ` `{ ` `    ``// create a binary tree ` `    ``node* root = getnode(20); ` `    ``root->left = getnode(10); ` `    ``root->right = getnode(30); ` `    ``root->left->left = getnode(5); ` `    ``root->left->right = getnode(15); ` `    ``root->left->right->left = getnode(12); ` `    ``root->right->left = getnode(25); ` `    ``root->right->right = getnode(40); ` ` `  `    ``// return level of node ` `    ``int` `level = getlevel(root, 30); ` `    ``(level != 0) ? (cout << ``"level of node 30 is "` `<< level << endl) :  ` `                   ``(cout << ``"node 30 not found"` `<< endl); ` ` `  `    ``level = getlevel(root, 12); ` `    ``(level != 0) ? (cout << ``"level of node 12 is "` `<< level << endl) :  ` `                   ``(cout << ``"node 12 not found"` `<< endl); ` ` `  `    ``level = getlevel(root, 25); ` `    ``(level != 0) ? (cout << ``"level of node 25 is "` `<< level << endl) :  ` `                   ``(cout << ``"node 25 not found"` `<< endl); ` ` `  `    ``level = getlevel(root, 27); ` `    ``(level != 0) ? (cout << ``"level of node 27 is "` `<< level << endl) :  ` `                   ``(cout << ``"node 27 not found"` `<< endl); ` `    ``return` `0; ` `} `

## Python3

# Python3 program to find closest
# value in Binary search Tree

_MIN = -2147483648
_MAX = 2147483648

# Helper function that allocates a new
# node with the given data and None
# left and right poers.
class getnode:

# Constructor to create a new node
def __init__(self, data):
self.data = data
self.left = None
self.right = None

# utility function to return level
# of given node
def getlevel(root, data):

q = []
level = 1
q.append(root)

# extra None is appended to keep track
# of all the nodes to be appended
# before level is incremented by 1
q.append(None)
while (len(q)):
temp = q
q.pop(0)
if (temp == None) :
if len(q) == 0:
return 0
if (q != None):
q.append(None)
level += 1
else :
if (temp.data == data) :
return level
if (temp.left):
q.append(temp.left)
if (temp.right) :
q.append(temp.right)
return 0

# Driver Code
if __name__ == ‘__main__’:

# create a binary tree
root = getnode(20)
root.left = getnode(10)
root.right = getnode(30)
root.left.left = getnode(5)
root.left.right = getnode(15)
root.left.right.left = getnode(12)
root.right.left = getnode(25)
root.right.right = getnode(40)

# return level of node
level = getlevel(root, 30)
if level != 0:
print(“level of node 30 is”, level)
else:

level = getlevel(root, 12)
if level != 0:
print(“level of node 12 is”, level)
else:

level = getlevel(root, 25)
if level != 0:
print(“level of node 25 is”, level)
else:

level = getlevel(root, 27)
if level != 0:
print(“level of node 27 is”, level)
else:

# This code is contributed by
# Shubham Singh(SHUBHAMSINGH10)

Output:

```level of node 30 is 2
level of node 12 is 4
level of node 25 is 3
```

## tags:

Tree tree-level-order Tree