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Find all elements in array which have at-least two greater elements

Given an array of n distinct elements, the task is to find all elements in array which have at-least two greater elements than themselves.

Examples :

Input : arr[] = {2, 8, 7, 1, 5};
Output : 2  1  5  
The output three elements have two or
more greater elements
      
Input  : arr[] = {7, -2, 3, 4, 9, -1};
Output : -2  3  4 -1  



Method 1 (Simple)
The naive approach is to run two loops and check one by one element of array check that array elements have at-least two elements greater than itself or not. If its true then print array element.

C++

// Simple C++ program to find
// all elements in array which 
// have at-least two greater 
// elements itself.
#include<bits/stdc++.h>
using namespace std;
  
void findElements(int arr[], int n)
{
    // Pick elements one by one and 
    // count greater elements. If 
    // count is more than 2, print 
    // that element.
    for (int i = 0; i < n; i++)
    {
        int count = 0;
        for (int j = 0; j < n; j++)
            if (arr[j] > arr[i])
                count++;
  
        if (count >= 2)
            cout << arr[i] << " ";
    }
}
  
// Driver code
int main()
{
    int arr[] = { 2, -6 ,3 , 5, 1};
    int n = sizeof(arr) / sizeof(arr[0]);
    findElements(arr, n);
    return 0;
}

Java

// Java program to find all 
// elements in array which 
// have at-least two greater
// elements itself.
import java.util.*;
import java.io.*;
  
class GFG
{
      
static void findElements(int arr[], 
                            int n)
{
    // Pick elements one by one 
    // and count greater elements. 
    // If count is more than 2, 
    // print that element.
    for (int i = 0; i < n; i++)
    {
        int count = 0;
          
        for (int j = 0; j < n; j++)
            if (arr[j] > arr[i])
                count++;
  
        if (count >= 2)
        System.out.print(arr[i] + " ");
    }
}
  
// Driver code
public static void main(String args[])
{
    int arr[] = { 2, -6 ,3 , 5, 1};
    int n = arr.length;
    findElements(arr, n);
}
}
  
// This code is contributed by Sahil_Bansall

Python3

# Python3 program to find
# all elements in array
# which have at-least two
# greater elements itself.
  
def findElements( arr, n):
  
    # Pick elements one by
        # one and count greater
    # elements. If count
        # is more than 2, print
    # that element.
  
    for i in range(n):
        count = 0
        for j in range(0, n):
            if arr[j] > arr[i]:
                count = count + 1
                  
                  
                  
        if count >= 2 :
            print(arr[i], end=" ")
              
  
# Driver code
arr = [ 2, -6 ,3 , 5, 1]
n = len(arr)
findElements(arr, n)
      
# This code is contributed by sunnysingh

C#

// C# program to find all elements in
// array which have at least two greater
// elements itself.
using System;
  
class GFG
{
      
static void findElements(int []arr, int n)
{
    // Pick elements one by one and count 
    // greater elements. If count is more 
    // than 2, print that element.
    for (int i = 0; i < n; i++)
    {
        int count = 0;
          
        for (int j = 0; j < n; j++)
            if (arr[j] > arr[i])
                count++;
  
        if (count >= 2)
    Console.Write(arr[i] + " ");
    }
}
  
// Driver code
public static void Main(String []args)
{
    int []arr = {2, -6 ,3 , 5, 1};
    int n = arr.Length;
    findElements(arr, n);
  
}
}
  
// This code is contributed by Parashar.

PHP

<?php
// Simple PHP program to find 
// all elements in array which
// have at-least two greater
// elements itself.
  
function findElements($arr, $n)
{
    // Pick elements one by one and
    // count greater elements. If 
    // count is more than 2, 
    // print that element.
    for ($i = 0; $i < $n; $i++)
    {
        $count = 0;
        for ($j = 0; $j < $n; $j++)
            if ($arr[$j] > $arr[$i])
                $count++;
  
        if ($count >= 2)
            echo $arr[$i]." ";
    }
}
  
// Driver code
$arr = array( 2, -6 ,3 , 5, 1);
$n = sizeof($arr);
findElements($arr, $n);
  
?>


Output :

2  -6  1


Time Complexity :
O(n2)

 
Method 2 (Use Sorting)
We sort the array first in increasing order, then we print first n-2 elements where n is size of array.

C++

// Sorting based C++ program to 
// find all elements in array 
// which have atleast two greater 
// elements itself.
#include<bits/stdc++.h>
using namespace std;
  
void findElements(int arr[], int n)
{
    sort(arr, arr + n);
  
    for (int i = 0; i < n - 2; i++)
    cout << arr[i] << " ";
}
  
// Driver Code
int main()
{
    int arr[] = { 2, -6 ,3 , 5, 1};
    int n = sizeof(arr) / sizeof(arr[0]);
    findElements(arr, n);
    return 0;
}

Java

// Sorting based Java program to find 
// all elements in array which have 
// atleast two greater elements itself.
import java.util.*;
import java.io.*;
  
class GFG
{
  
static void findElements(int arr[], int n)
{
    Arrays.sort(arr);
  
    for (int i = 0; i < n - 2; i++)
    System.out.print(arr[i] + " ");
}
  
// Driver code
public static void main(String args[])
{
    int arr[] = { 2, -6 ,3 , 5, 1};
    int n = arr.length;
    findElements(arr, n);
  
}
}
  
// This code is contributed by Sahil_Bansall

Python3

# Sorting based Python 3 program
# to find all elements in array 
# which have atleast two greater 
# elements itself.
  
def findElements(arr, n):
  
    arr.sort()
  
    for i in range(0, n-2):
        print(arr[i], end =" ")
  
# Driven source
arr = [2, -6, 3, 5, 1]
n = len(arr)
findElements(arr, n)
  
# This code is contributed 
# by Smitha Dinesh Semwal

Output :

-6 1 2

C#

// Sorting based C# program to find 
// all elements in array which have 
// atleast two greater elements itself.
using System;
  
class GFG
{
  
static void findElements(int []arr, int n)
{
    Array.Sort(arr);
  
    for (int i = 0; i < n-2; i++)
        Console.Write(arr[i] + " ");
}
  
// Driver code
public static void Main(String []args)
{
    int []arr = { 2, -6 ,3 , 5, 1};
    int n = arr.Length;
    findElements(arr, n);
  
}
}
  
// This code is contributed by parashar

PHP

<?php
// Sorting based PHP program to 
// find all elements in array 
// which have atleast two greater
// elements itself.
  
function findElements( $arr, $n)
{
    sort($arr);
  
    for ($i = 0; $i < $n - 2; $i++)
    echo $arr[$i] , " ";
}
  
// Driver Code
$arr = array( 2, -6 ,3 , 5, 1);
$n = count($arr);
findElements($arr, $n); 
  
// This code is contributed by anuj_67.
?>;


Output :

-6 1 2

Time Complexity : O(n Log n)

 
Method 3 (Efficient)
In second method we simply calculate second maximum element of array and print all element which is less than or equal to second maximum.

C++

// C++ program to find all elements
// in array which have atleast two 
// greater elements itself.
#include<bits/stdc++.h>
using namespace std;
  
void findElements(int arr[], int n)
{
    int first = INT_MIN, 
        second = INT_MIN;
    for (int i = 0; i < n; i++)
    {
        /* If current element is smaller 
        than first then update both first 
        and second */
        if (arr[i] > first)
        {
            second = first;
            first = arr[i];
        }
  
        /* If arr[i] is in between first 
        and second then update second */
        else if (arr[i] > second)
            second = arr[i];
    }
  
    for (int i = 0; i < n; i++)
        if (arr[i] < second)
            cout << arr[i] << " ";
}
  
// Driver code
int main()
{
    int arr[] = { 2, -6, 3, 5, 1};
    int n = sizeof(arr) / sizeof(arr[0]);
    findElements(arr, n);
    return 0;
}

Java

// Java program to find all elements
// in array which have atleast
// two greater elements itself.
import java.util.*;
import java.io.*;
  
class GFG
{
      
static void findElements(int arr[], int n)
{
    int first = Integer.MIN_VALUE;
    int second = Integer.MAX_VALUE;
      
    for (int i = 0; i < n; i++)
    {
        // If current element is smaller 
        // than first then update both
        // first and second 
        if (arr[i] > first)
        {
            second = first;
            first = arr[i];
        }
  
        /* If arr[i] is in between 
        first and second
        then update second */
        else if (arr[i] > second)
            second = arr[i];
    }
  
    for (int i = 0; i < n; i++)
        if (arr[i] < second)
            System.out.print(arr[i] + " ") ;
}
// Driver code
public static void main(String args[])
{
    int arr[] = { 2, -6, 3, 5, 1};
    int n = arr.length;
    findElements(arr, n);
}
}
  
// This code is contributed by Sahil_Bansall

Python3

# Python 3 program to find all elements
# in array which have atleast two 
# greater elements itself.
import sys
  
def findElements(arr, n):
  
    first = -sys.maxsize
    second = -sys.maxsize
  
    for i in range(0, n):
      
        # If current element is smaller
        # than first then update both
        # first and second 
        if (arr[i] > first):
          
            second = first
            first = arr[i]
          
        # If arr[i] is in between first
        # and second then update second 
        elif (arr[i] > second):
            second = arr[i]
      
    for i in range(0, n):
        if (arr[i] < second):
            print(arr[i], end =" ")
  
  
# Driver code
arr = [2, -6, 3, 5, 1]
n = len(arr)
findElements(arr, n)
  
# This code is contributed
# by Smitha Dinesh Semwal

C#

// C# program to find all elements
// in array which have atleast
// two greater elements itself.
using System;
  
class GFG
{
    static void findElements(int []arr, 
                            int n)
    {
    int first = int.MinValue;
    int second = int.MaxValue;
      
    for (int i = 0; i < n; i++)
    {
        // If current element is smaller 
        // than first then update both 
        // first and second 
        if (arr[i] > first)
        {
            second = first;
            first = arr[i];
        }
  
        /* If arr[i] is in between 
        first and second
        then update second */
        else if (arr[i] > second)
            second = arr[i];
    }
  
    for (int i = 0; i < n; i++)
        if (arr[i] < second)
            Console.Write(arr[i] + " ") ;
}
// Driver code
public static void Main(String []args)
{
    int []arr = { 2, -6, 3, 5, 1};
    int n = arr.Length;
    findElements(arr, n);
}
}
  
// This code is contributed by parashar...

PHP

<?php
// PHP program to find all elements
// in  array which have atleast two 
// greater elements itself.
  
function findElements($arr, $n)
{
      
    $first = PHP_INT_MIN; 
    $second =  PHP_INT_MIN;
    for ($i = 0; $i < $n; $i++)
    {
          
            /* If current element is smaller 
            than first then update both first 
            and second */
            if ($arr[$i] > $first)
            {
                $second = $first;
                $first = $arr[$i];
              
      
            }
  
        /* If arr[i] is in between first 
           and second then update second */
        else if ($arr[$i] > $second)
            $second = $arr[$i];
    }
  
    for($i = 0; $i < $n; $i++)
        if ($arr[$i] < $second)
            echo $arr[$i] , " ";
}
  
    // Driver code
    $arr = array(2, -6, 3, 5, 1);
    $n = count($arr);
    findElements($arr, $n);
  
// This code is contributed by vishal tripathi.
?>


Output :

2  -6  1

Time Complexity : O(n)

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.



This article is attributed to GeeksforGeeks.org

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