**Arden’s theorem** state that:

“If P and Q are two regular expressions over , and if P does not contain , then the following equation in R given by R = Q + RP has a unique solution i.e., R = QP*.”

That means, whenever we get any equation in the form of R = Q + RP, then we can directly replaced by R = QP*. So, here first we will prove that R = QP* is the solution of this equation and then we will also prove that it is the unique solution of this equation.

Let’s start by taking this equation as equation (i)

R = Q + RP ......(i)

Now, replacing R by R = QP*, we get,

R = Q + QP*P

Taking Q as common,

R = Q( + P*P) R = QP*

(As we know that + R*R = R*). Hence proved.

*Thus, R = QP* is the solution of the equation R = Q + RP.*

Now, we have to prove that this is the only solution of this equation. Let me take this equation again:

R = Q + RP

Now, replace R by R = Q + RP,

R = Q + (Q + RP)P = Q + QP + R

Again, replace R by R = Q + RP:-

R = Q + QP + (Q + RP) = Q + QP + Q + R = ... = ... = Q + QP + Q + .. + Q + R

Now, replace R by R = QP*, we get,

R = Q + QP + Q + .. + Q + QP*

Taking Q as common,

R = Q( + P + + .. + + P*) = QP* [As + P + + .. + + P* represent the closure of P]

Hence proved.

**Thus, R = QP* is the unique solution of the equation R = Q + RP. **

To understand this theorem, we will solve an example:

**Example –**

q1 = q1.0 + q2 = q1.1 + q2.0 q3 = q2.1 + q3.0 + q3.1

Now,

q1 = + q1.0 q1 = .0* [By Arden's theorem] q1 = 0* [R = R] .'. q2 = 0*1 +q2.0 q2 = 0*10*

[Applying Arden’s theorem]. Hence, the value of q2 is 0*10*.

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