Given a number n, we need to find the maximum number of times n circles intersect.
Examples:
Input : n = 2 Output : 2 Input : n = 3 Output : 6![]()
Description and Derivation
As we can see in above diagram, for each pair of circles, there can be maximum two intersectuib points. Therefore if we have n circles then there can be nC2 pairs of circles in which each pair will have two intersections. So by this we can conclude that by looking at all possible pairs of circles the mathematical formula can be made for the maximum number of intersection by n circles is given by 2 * nC2.
2 * nC2 = 2 * n * (n – 1)/2 = n * (n-1)
C++
// CPP program to find maximum umber of // intersections of n circles #include <bits/stdc++.h> using namespace std; // Returns maximum number of intersections int intersection( int n) { return n * (n - 1); } int main() { cout << intersection(3) << endl; return 0; } // This code is contributed by // Manish Kumar Rai. |
Java
// Java program to find maximum umber of // intersections of n circles import java.io.*; public class GFG { // for the calculation of 2*(nC2) static int intersection( int n) { return n * (n - 1 ); } public static void main(String[] args) throws IOException { System.out.println(intersection( 3 )); } } // This code is contributed by // Manish Kumar Rai |
Python3
# python program to find maximum umber of # intersections of n circles # Returns maximum number of intersections def intersection(n): return n * (n - 1 ); # Drive code print (intersection( 3 )) # This code is contributed by Sam007 |
C#
// C# program to find maximum umber of // intersections of n circles using System; class GFG { // for the calculation of 2*(nC2) static int intersection( int n) { return n * (n - 1); } // Driver Code public static void Main() { Console.WriteLine(intersection(3)); } } // This code is contributed by Sam007 |
php
<?php // php program to find maximum umber of // intersections of n circles // Returns maximum number of intersections function intersection( $n ) { return $n * ( $n - 1); } // Drive code echo intersection(3); // This code is contributed by Sam007 ?> |
Output:
6
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