# Multiply a given Integer with 3.5

Given a integer x, write a function that multiplies x with 3.5 and returns the integer result. You are not allowed to use %, /, *.

```Examples :
Input: 2
Output: 7

Input: 5
Output: 17 (Ignore the digits after decimal point)
```

Solution:
1. We can get x*3.5 by adding 2*x, x and x/2. To calculate 2*x, left shift x by 1 and to calculate x/2, right shift x by 2.

## C++

 `// C++ program to multiply ` `// a number with 3.5 ` `#include ` ` `  `int` `multiplyWith3Point5(``int` `x) ` `{ ` `    ``return` `(x<<1) + x + (x>>1); ` `}  ` ` `  `/* Driver program to test above functions*/` `int` `main() ` `{ ` `    ``int` `x = 4;  ` `    ``printf``(``"%d"``, multiplyWith3Point5(x)); ` `    ``getchar``(); ` `    ``return` `0; ` `} `

## Java

 `// Java Program to multiply ` `// a number with 3.5 ` ` `  `class` `GFG { ` `         `  `    ``static` `int` `multiplyWith3Point5(``int` `x) ` `    ``{ ` `        ``return` `(x<<``1``) + x + (x>>``1``); ` `    ``}  ` `     `  `    ``/* Driver program to test above functions*/` `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` `        ``int` `x = ``2``;  ` `        ``System.out.println(multiplyWith3Point5(x)); ` `    ``} ` `} ` ` `  `// This code is contributed by prerna saini. `

## Python3

 `# Python 3 program to multiply ` `# a number with 3.5 ` ` `  `def` `multiplyWith3Point5(x): ` ` `  `    ``return` `(x<<``1``) ``+` `x ``+` `(x>>``1``) ` `  `  ` `  `# Driver program to  ` `# test above functions ` `x ``=` `4`  `print``(multiplyWith3Point5(x)) ` ` `  `# This code is contributed by ` `# Smitha Dinesh Semwal `

## C#

 `// C# Program to multiply ` `// a number with 3.5 ` `using` `System; ` ` `  `class` `GFG ` `{ ` `         `  `    ``static` `int` `multiplyWith3Point5(``int` `x) ` `    ``{ ` `        ``return` `(x<<1) + x + (x>>1); ` `    ``}  ` `     `  `    ``/* Driver program to test above functions*/` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `x = 2;  ` `        ``Console.Write(multiplyWith3Point5(x)); ` `    ``} ` `     `  `} ` ` `  `// This code is contributed by Sam007 `

## PHP

 `> 1); ` `}  ` ` `  `// Driver Code ` `\$x` `= 4;  ` `echo` `multiplyWith3Point5(``\$x``); ` `     `  `// This code is contributed by vt_m. ` `?> `

2. Another way of doing this could be (8*x – x)/2 (See below code). Thanks to Ajaym for suggesting this.

 `#include ` `int` `multiplyWith3Point5(``int` `x) ` `{ ` `  ``return` `((x<<3) - x)>>1; ` `}     `

Please write comments if you find the above code/algorithm incorrect, or find better ways to solve the same problem

## tags:

Bit Magic Bit Magic