Given two strings, find if first string is a subsequence of second

Given two strings str1 and str2, find if str1 is a subsequence of str2. A subsequence is a sequence that can be derived from another sequence by deleting some elements without changing the order of the remaining elements (source: wiki). Expected time complexity is linear.

Examples :

Input: str1 = "AXY", str2 = "ADXCPY"
Output: True (str1 is a subsequence of str2)

Input: str1 = "AXY", str2 = "YADXCP"
Output: False (str1 is not a subsequence of str2)

Input: str1 = "gksrek", str2 = "geeksforgeeks"
Output: True (str1 is a subsequence of str2)

The idea is simple, we traverse both strings from one side to other side (say from rightmost character to leftmost). If we find a matching character, we move ahead in both strings. Otherwise we move ahead only in str2.

Following is Recursive Implementationof the above idea.

C/C++

// Recursive C++ program to check if a string is subsequence of another string 
#include<iostream> 
#include<cstring> 
using namespace std; 
  
// Returns true if str1[] is a subsequence of str2[]. m is 
// length of str1 and n is length of str2 
bool isSubSequence(char str1[], char str2[], int m, int n) 
{ 
    // Base Cases 
    if (m == 0) return true; 
    if (n == 0) return false; 
  
    // If last characters of two strings are matching 
    if (str1[m-1] == str2[n-1]) 
        return isSubSequence(str1, str2, m-1, n-1); 
  
    // If last characters are not matching 
    return isSubSequence(str1, str2, m, n-1); 
} 
  
// Driver program to test methods of graph class 
int main() 
{ 
    char str1[] = "gksrek"; 
    char str2[] = "geeksforgeeks"; 
    int m = strlen(str1); 
    int n = strlen(str2); 
    isSubSequence(str1, str2, m, n)? cout << "Yes ": 
                                     cout << "No"; 
    return 0; 
} 

/div>

Java

// Recursive Java program to check if a string 
// is subsequence of another string 
import java.io.*; 
  
class SubSequence 
{ 
    // Returns true if str1[] is a subsequence of str2[] 
    // m is length of str1 and n is length of str2 
    static boolean isSubSequence(String str1, String str2, int m, int n) 
    { 
        // Base Cases 
        if (m == 0)  
            return true; 
        if (n == 0)  
            return false; 
              
        // If last characters of two strings are matching 
        if (str1.charAt(m-1) == str2.charAt(n-1)) 
            return isSubSequence(str1, str2, m-1, n-1); 
  
        // If last characters are not matching 
        return isSubSequence(str1, str2, m, n-1); 
    } 
      
    // Driver program 
    public static void main (String[] args)  
    { 
        String str1 = "gksrek"; 
        String str2 = "geeksforgeeks"; 
        int m = str1.length(); 
        int n = str2.length(); 
        boolean res = isSubSequence(str1, str2, m, n); 
        if(res) 
            System.out.println("Yes"); 
        else
            System.out.println("No"); 
    } 
} 
  
// Contributed by Pramod Kumar 

Python

# Recursive Python program to check if a string is subsequence 
# of another string 
  
# Returns true if str1[] is a subsequence of str2[]. m is 
# length of str1 and n is length of str2 
def isSubSequence(string1, string2, m, n): 
    # Base Cases 
    if m == 0:    return True
    if n == 0:    return False
  
    # If last characters of two strings are matching 
    if string1[m-1] == string2[n-1]: 
        return isSubSequence(string1, string2, m-1, n-1) 
  
    # If last characters are not matching 
    return isSubSequence(string1, string2, m, n-1) 
  
# Driver program to test the above function 
string1 = "gksrek"
string2 = "geeksforgeeks"
m = len(string1) 
n = len(string2) 
if isSubSequence(string1, string2, m, n): 
    print "Yes"
else: 
    print "No"
  
# This code is contributed by BHAVYA JAIN 

C#

// Recursive C# program to check if a string  
// is subsequence of another string 
using System; 
  
class GFG { 
      
    // Returns true if str1[] is a  
    // subsequence of str2[] m is  
    // length of str1 and n is length  
    // of str2 
    static bool isSubSequence(string str1, 
                  string str2, int m, int n) 
    { 
          
        // Base Cases 
        if (m == 0)  
            return true; 
        if (n == 0)  
            return false; 
              
        // If last characters of two strings 
        // are matching 
        if (str1[m-1] == str2[n-1]) 
            return isSubSequence(str1, str2, 
                                    m-1, n-1); 
  
        // If last characters are not matching 
        return isSubSequence(str1, str2, m, n-1); 
    } 
      
    // Driver program 
    public static void Main ()  
    { 
        string str1 = "gksrek"; 
        string str2 = "geeksforgeeks"; 
        int m = str1.Length; 
        int n = str2.Length; 
        bool res = isSubSequence(str1, str2, m, n); 
          
        if(res) 
            Console.Write("Yes"); 
        else
            Console.Write("No"); 
    } 
} 
  
// This code is contributed by nitin mittal. 

PHP

<?php 
// Recursive PHP program to check 
// if a string is subsequence of  
// another string 
  
// Returns true if str1[] is a  
// subsequence of str2[]. m is 
// length of str1 and n is  
// length of str2 
  
function isSubSequence($str1, $str2,  
                             $m, $n) 
{ 
    // Base Cases 
    if ($m == 0) return true; 
    if ($n == 0) return false; 
  
    // If last characters of two 
    // strings are matching 
    if ($str1[$m - 1] == $str2[$n - 1]) 
        return isSubSequence($str1, $str2, 
                          $m - 1, $n - 1); 
  
    // If last characters  
    // are not matching 
    return isSubSequence($str1, $str2,  
                          $m, $n - 1); 
} 
  
// Driver Code 
$str1= "gksrek"; 
$str2 = "geeksforgeeks"; 
$m = strlen($str1); 
$n = strlen($str2); 
  
$t = isSubSequence($str1, $str2, $m, $n) ?  
                                   "Yes ": 
                                     "No"; 
  
if($t = true) 
    echo "Yes"; 
else 
    echo "No"; 
  
// This code is contributed by ajit 
?> 

Output :

Yes

Following is the Iterative Implementation:

C/C++

// Iterative C++ program to check if a string is subsequence of another string 
#include<iostream> 
#include<cstring> 
using namespace std; 
  
// Returns true if str1[] is a subsequence of str2[]. m is 
// length of str1 and n is length of str2 
bool isSubSequence(char str1[], char str2[], int m, int n) 
{ 
   int j = 0; // For index of str1 (or subsequence 
  
   // Traverse str2 and str1, and compare current character  
   // of str2 with first unmatched char of str1, if matched  
   // then move ahead in str1 
   for (int i=0; i<n&&j<m; i++) 
       if (str1[j] == str2[i]) 
         j++; 
  
   // If all characters of str1 were found in str2 
   return (j==m); 
} 
  
// Driver program to test methods of graph class 
int main() 
{ 
    char str1[] = "gksrek"; 
    char str2[] = "geeksforgeeks"; 
    int m = strlen(str1); 
    int n = strlen(str2); 
    isSubSequence(str1, str2, m, n)? cout << "Yes ": 
                                     cout << "No"; 
    return 0; 
} 

Java

// Iterative Java program to check if a string  
// is subsequence of another string 
import java.io.*; 
  
class GFG { 
      
    // Returns true if str1[] is a subsequence  
    // of str2[] m is length of str1 and n is 
    // length of str2 
    static boolean isSubSequence(String str1,  
                    String str2, int m, int n) 
    { 
        int j = 0; 
          
        // Traverse str2 and str1, and compare  
        // current character of str2 with first 
        // unmatched char of str1, if matched  
        // then move ahead in str1 
        for (int i = 0; i < n && j < m; i++) 
            if (str1.charAt(j) == str2.charAt(i)) 
                j++; 
  
        // If all characters of str1 were found 
        // in str2 
        return (j == m);  
    } 
      
    // Driver program to test methods of 
    // graph class 
    public static void main (String[] args)  
    { 
        String str1 = "gksrek"; 
        String str2 = "geeksforgeeks"; 
        int m = str1.length(); 
        int n = str2.length(); 
        boolean res = isSubSequence(str1, str2, m, n); 
          
        if(res) 
            System.out.println("Yes"); 
        else
            System.out.println("No"); 
    } 
} 
  
// This code is contributed by Pramod Kumar 

Python

# Iterative Python program to check if a string is subsequence of another string 
  
# Returns true if str1 is a subsequence of str2 
# m is length of str1, n is length of str2 
def isSubSequence(str1,str2,m,n): 
      
    j = 0    # Index of str1 
    i = 0    # Index of str2 
      
    # Traverse both str1 and str2 
    # Compare current character of str2 with  
    # first unmatched character of str1 
    # If matched, then move ahead in str1 
      
    while j<m and i<n: 
        if str1[j] == str2[i]:     
            j = j+1    
        i = i + 1
          
    # If all characters of str1 matched, then j is equal to m 
    return j==m 
      
# Driver Program 
  
str1 = "gksrek"
str2 = "geeksforgeeks"
m = len(str1) 
n = len(str2) 
  
print "Yes" if isSubSequence(str1,str2,m,n) else "No"
  
# Contributed by Harshit Agrawal 

C#

// Iterative C# program to check if a string  
// is subsequence of another string 
using System; 
  
class GFG { 
      
    // Returns true if str1[] is a subsequence 
    // of str2[] m is length of str1 and n is  
    // length of str2 
    static bool isSubSequence(string str1,  
                     string str2, int m, int n) 
    { 
        int j = 0; 
          
        // Traverse str2 and str1, and compare 
        // current character of str2 with first 
        // unmatched char of str1, if matched  
        // then move ahead in str1 
        for (int i = 0; i < n && j < m; i++) 
            if (str1[j] == str2[i]) 
                j++; 
  
        // If all characters of str1 were found 
        // in str2 
        return (j == m);  
    } 
      
    // Driver program to test methods of  
    // graph class 
    public static void Main ()  
    { 
        String str1 = "gksrek"; 
        String str2 = "geeksforgeeks"; 
        int m = str1.Length; 
        int n = str2.Length; 
        bool res = isSubSequence(str1, str2, m, n); 
          
        if(res) 
            Console.WriteLine("Yes"); 
        else
            Console.WriteLine("No"); 
    } 
} 
  
// This code is contributed by anuj_67. 

PHP

<?php 
// Iterative PHP program to check if  
// a string is subsequence of another 
// string 
  
// Returns true if str1[] is  
// a subsequence of str2[]. 
// m is length of str1 and n  
// is length of str2 
function isSubSequence($str1, $str2, 
                             $m, $n) 
{ 
    // For index of str1 
    $j = 0;  
      
    // Traverse str2 and str1,  
    // and compare current  
    // character of str2 with  
    // first unmatched char of 
    // str1, if matched then  
    // move ahead in str1 
    for($i = 0; $i < $n and
        $j < $m; $i++) 
        if ($str1[$j] == $str2[$i]) 
            $j++; 
      
    // If all characters of  
    // str1 were found in str2 
    return ($j == $m); 
} 
  
    // Driver Code 
    $str1 = "gksrek"; 
    $str2 = "geeksforgeeks"; 
    $m = strlen($str1); 
    $n = strlen($str2); 
      
    if(isSubSequence($str1, $str2, $m, $n)) 
        echo "Yes "; 
    else
        echo "No"; 
  
// This code is contributed by anuj_67. 
?> 

Output:

Yes

Asked in:

Time Complexity of both implementations above is O(n) where n is the length of str2.

Given two strings, find if first string is a subsequence of second

C/C++

Java

Python

C#

PHP

C/C++

Java

Python

C#

PHP

Asked in:

tags:

You Might Also Like

leave a comment

0 Comments

Subscribe to Our Newsletter

Top Followed books